hasil dari √12+√27+√48-√3

[tex] \sqrt{12} + \sqrt{27} + \sqrt{48} - \sqrt{3} \\ = \sqrt{4 \times 3} + \sqrt{9 \times 3} + \sqrt{16 \times 3} - \sqrt{3} \\ = 2 \sqrt{3} + 3 \sqrt{3} + 4 \sqrt{3} - \sqrt{3} \\ = (2 + 3 + 4 - 1) \sqrt{3} \\ = 8 \sqrt{3} [/tex]