dik:Np=1000 Ns=400 Ip= 12 mA Vs=6V Ditanya Is dan Ip Sekalian cara penyelesaiannya

diket :
Np = 1000
Ns = 400
Ip = 12 mA = 0,012 A
Vs = 6 v
dit: Is & Ip
Jwb :
# Tegangan primer
Vp = ( Np . Vs ) / Ns
Vp = ( 1000 . 6 ) / 400
Vp = 6000 / 400
Vp = 15 volt

# Arus primer
Ip = 12 mA / 1000
Ip = 0,012 A

# Arus sekunder
Is = ( Ip . Vp ) / Vs
Is = ( 0,012 . 15 ) / 6
Is = 0,18 / 6
Is = 0,03 A