[tex]jika \: g(x) = \frac{x + 1}{x - 1} dan \: (g \: o \: f) \: (x) = \: \frac{x + 2}{x} \: \: maka \: f(2) = [/tex]

[tex] g(f(x)) = \frac{x+2}{x} \\ \frac{f(x) + 1}{f(x) - 1} = \frac{x + 2}{x} \\ x.f(x) + x = x.f(x) - x + 2.f(x) - 2 \\ 2x + 2 = 2.f(x) \\ f(x) = x + 1 \\ f(2) = 2 + 1 = 3 [/tex]