Bentuk sederhana dari [tex] \frac{6}{ \sqrt{7} + 2} \: adalah......[/tex]

[tex] \frac{6}{ \sqrt{7} + 2} \times \frac{ \sqrt{7} - 2}{ \sqrt{7} - 2} = \frac{6 \sqrt{7} - 12}{7 - 4} = \frac{6 \sqrt{7} - 12}{3} = 2 \sqrt{7} - 4[/tex]
maaf klu salahh

Operasi Bentuk Akar

[tex] \frac{6}{ \sqrt{7} + 2 } = \frac{6}{ \sqrt{7} + 2} \times \frac{ \sqrt{7} - 2}{ \sqrt{7} - 2} \\ \\ = \frac{6 \sqrt{7} - 12}{7 - 4} \\ \\ = \frac{6 \sqrt{7} - 12 }{3} \\ \\ = 2 \sqrt{7} - 4[/tex]


*semoga semoga​. sukses selalu ^_^