Turunan fungsi aljabar f(x)=(4x+1) (2x-1)

Kelas 11 Matematika
Bab Turunan

f(x) = (4x + 1) (2x - 1)
f(x) = 8x² - 4x + 2x - 1
f(x) = 8x² - 2x - 1
f'(x) = 16x - 2

cara 1.
f (x) = (4x +1)(2x - 1)
f (x) = 8x^2 -2x -1
f'(x) = 16x -2
cara 2, dengan menggunakan rumus perkakian 2,fungsi.
f (x) = u.v
f'(x) = u'.v + u.v'
f (x) = (4x +1)(2x -1)
u = 4x +1, => u' = 4
v = 2x - 1, => v' = 2
f'(x) = 4(2x -1) + (4x +1).2
f'(x) = 8x - 4 + 8x +2
f'(x) = 16x - 2