jika sec a= 13/12 maka cot a =...

Kelas 10 Matematika
Bab Trigonometri

sec a = 13/12 → r/x

y = √(r² - x²)
y = √(13² - 12²)
y = √(169 - 144)
y = √25
y = 5

cot a = x/y
cot a = 12/5

sec a = 13/12
1/cos a = 13/12
cos a = 12/13
(cos =sisi samping/sisi miring)
Sisi depan(menggunakan pytagoras)
Sehingga didapat sisi depan = 5

Sin a = depan / miring
Sin a =5/13

Cot a = cos a/ sin a
Cot a = (12/13) / (5/13)
Cot a = 12/5