Suatu persegi panjang,panjangnya 17 2/5 cm lebarnya 12 1/4 cm.a.Hitunglah kelilingnya! b.Hitunglah pula luasnya!

a. k = 2 (p + l)
= 2 (17 2/5 + 12 1/4)
= 2 (87/5 + 49/4)
= 2 (348/20 + 254/20)
= 2 (602/20)
= 60 1/5 cm
b. L = p × l
= 17 2/5 x 12 1/4
= 87/5 x 49/4
= 4263/20
= 213 3/20 cm^2

Keliling = 2 x ( 17[tex] \frac{2}{5} [/tex] + 12 [tex] \frac{1}{4} [/tex] )
             = 2 ( 29[tex] \frac{13}{20} [/tex] )
             = 59 [tex] \frac{3}{10} [/tex] cm     atau 59,3 cm  


Luas    = 17[tex] \frac{2}{5} [/tex] x 12 [tex] \frac{1}{4} [/tex]
            =213,15 cm²