tentukan persamaan garis yang tega lurus 2y+2= -7/4 (x-7) dan melalui titik (-2,-3). bantuiin yaaaaa

Garis pertama:
[tex]2y+2= \frac{-7}{4} (x-7) ->Kalisilang \\ 4(2y+2)=-7(x-7) \\ 8y+8 = -7x+7 \\ 8y= -7x+7-8 \\ 8y=-7x-1 \\ y= -7/8x -1/8 \\ m1=-7/8 [/tex]

m1xm2=-1
-7/8 x m2 =-1
         m2  = -1 x -8/7
         m2 = 8/7


Garis kedua:

x1 = -2 y1=-3 m2 = 8/7

[tex] y-y1 = m(x-x1) \\ y-(-3)= \frac{8}{7}(x-(-2)) \\ y+3= \frac{8}{7} (x+2) ->(Kalisilang) \\ 7(y+3) = 8(x+2) \\ 7y+21 = 8x+16 \\ 7y=8x+16-21 \\ 7y=8x-5 \\ y= \frac{7}{8}x- \frac{5}{8} [/tex]