Hitunglah konsentrasi asam basa ph asam = 0 Ph basa = 12 Ph netral = 7 Ph asam = 3 Ph netral = 7
Kimia
lelirizkirahmawati
Pertanyaan
Hitunglah konsentrasi asam basa
ph asam = 0
Ph basa = 12
Ph netral = 7
Ph asam = 3
Ph netral = 7
ph asam = 0
Ph basa = 12
Ph netral = 7
Ph asam = 3
Ph netral = 7
1 Jawaban
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1. Jawaban rezairfani23
pH = - log [H+]
pH asam = 0, maka - log 10^0
[H+] = 1
pH basa = 12, maka pOH = pKw - pH = 1 4 - 12 = 2
pOH = - log [OH-]
2 = - log [OH-]
[OH-] = 10^-2
pH netral = 7
pH = - log [H+]
7 = - log [H+]
[H+] = 10^-7
pH asam = 3
pH = - log [H+]
3 = - log [H+]
[H+] = 10^-3