tranformator step up mempunyai jumlah lilitan kumparan primer 400 lilitan dan kumparan sekundernya 20.000 lilitan jika tegangan nya pada kumparan primer 20V dan

diket :
Np = 400
Ns = 20.000
Vp = 20 v
Ip = 10 A
dit : Pp , Vs , Is ideal & Is jk ef 80% ?
Jwb :
# Daya primer
Pp = Ip . Vp
Pp = 10 . 20
Pp = 200 watt

# Tegangan sekunder
Vs = ( Ns . Vp ) / Np
Vs = ( 20.000 . 20 ) / 400
Vs = 400.000 / 400
Vs = 1000 volt

#Arus sekunder bila ideal
Is = ( Ip . Vp ) / Vs
Is = ( 10 . 20 ) / 1000
Is = 200 / 1000
Is = 0,2 A

# Daya sekunder jk ef 80 %
Ps = ( Pp . ef ) . 100%
Ps = ( 200 . 80% ) . 100%
Ps = ( 200 . 0,8 ) . 1
Ps = 160 watt

# Arus sekunder jk ef 80%
Is = Ps / Vs
Is = 160 / 1000
Is = 0,16 A