Dua buah lampu masing2 100 watt, 110 voltdipasang seri oada beda potensial 110 volt, daya yang dipakai tiap lampu

diket :
P1 = 2 x 100 w
V = 110 v
seri
dit ; Daya terpakai ( P2 )
Jwb :
# Kita cari hambatan lampu dl
R = V^2 / P1
R = 110^2 / 100
R = 12.100 / 100
R = 121 ohm

# Total hambatan
Rs = 2 . R
Rs = 2 . 121
Rs = 242 ohm

# Arus
I = V / Rs
I = 110 / 242
I = 0,454 A
Krn seri Arus tiap lampu sama

# Daya terpakai tiap lampu
P2 = V . I
P2 = 110 . 0,454
P2 = 49,94 watt ( 50 watt )

Jadi daya terpakai tiap lampu masing masing 50 watt