Matematika

Pertanyaan

jika f(x) =2xpangkat2+3x+1 maka nilai f(x-1)

1 Jawaban

  • f(x) = 2x²+3x+1
    f(x-1) = 2(x-1)²+3(x-1)+1
    f(x-1) = 2 ( x²-2x+1) + 3x-3 + 1
    f(x-1) = 2x²-4x+2 + 3x -2
    f(x-1) = 2x²-x
    f(x-1) = x (2x-1)

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