1.Tentukan persamaan garis yang memiliki gradien 3 dan melalui titik (-1,2) 2.Persamaan garis yang melalui titik (5,-4) dan bergradien 5 3.Tentukan persamaan ga

1. y - y1 = m (x - x1)
   y - 2 = 3 (x+1)
   y - 2 = 3x + 3
   y = 3x +5

2. y - y1 = m (x-x1)
    y + 4 = 5(x-5)
    y + 4 = 5x -25
   y = 5x - 29

3. y-y1 / y2 - y1 = x -x1 / x2-x1
  = y +3 / 0 + 3 = x - 2 / -1 -2
  = y + 3 / 3 = x-2/-3
  = -3(y + 3) = 3(x-2)
  3x + 3y + 9 = 0
  x + y + 3 = 0

4. y - 0/-2-0 = x+4/0+4
   y-0/-2 = x+ 4/4
 4y - 0 = -2x -8
 2x + 4y + 8 = 0
 x + 2y + 4 = 0

5. y-y1 = m (x-x1)
   y + 3 = 0 (x+1)
   y = -3

1. = y-y1 = m(x-x1)
    = y-2 = 3(x-(-1))
    = y-2 = 3(x+1)
    = y-2 = 3x+3
    = y-3x-2-3 = 0
    = y-3x-5 = 0


2. = y-y1 = m(x-x1)
    = y-(-4) = 5(x-5)
    = y+4 = 5x-25
    = y-5x+4+25 = 0
    =y-5x+29 = 0

3. = y-y1 : y2-y1 = x-x1 : x2-x1
    = y-(-3) : 0-(-3) = x-2 : -1-2
    = y+3 : 3 = x-2 : -3
    = -3(y+3) = 3(x-2)
    = -3y-9 = 3x-6
    = -3y-3x-9+6 = 0
    = -3y-3x-3 = 0

4. = y-y1 : y2-y1 = x-x1 : x2-x1
    = y-0 : -2-0 = x-(-4) : 0-(-4)
    = y-0 : -2 = x+4 : 4
    = 4(y-0) = -2(x+4)
    = 4y = -2x-8
    = 4y+2x+8 = 0

5. = y-y1 = m(x-x1)
    = y-(-3) = 0(x-(-1))
    = y+3 = 0(x+1)
    = y+3 = 0