Kak bantuin aku kerjain mtk donk plisss Berapa hasil dari : 1. Sin 135° + cos 135° = 2. Sin 120° + cos 150° = 3. Cos 120 + sin 150° = 4. Tan 45°. Sin 45° = 5. C
Matematika
mila639
Pertanyaan
Kak bantuin aku kerjain mtk donk plisss
Berapa hasil dari :
1. Sin 135° + cos 135° =
2. Sin 120° + cos 150° =
3. Cos 120 + sin 150° =
4. Tan 45°. Sin 45° =
5. Cos 45°. Tan 45° =
Berapa hasil dari :
1. Sin 135° + cos 135° =
2. Sin 120° + cos 150° =
3. Cos 120 + sin 150° =
4. Tan 45°. Sin 45° =
5. Cos 45°. Tan 45° =
2 Jawaban
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1. Jawaban asobri68
1. sin 135° + cos 135° = ((√2)/2) - ((√2)/2) = 0
2. sin 120° + cos 150° = ((√3)/2) - ((√3)/2) = 0
3. cos 120 + sin 150° = -(1/2) + (1/2) = 0
4. tan 45°. sin 45° = 1 . ((√2)/2) = (√2)/2
5. cos 45°. tan 45° = ((√2)/2) . 1 = (√2)/2 -
2. Jawaban FransiskusAsissiDAN
1
[tex]sin {45}^{0} - cos{45}^{0} \\ \sqrt{2} \times \frac{1}{2} - \sqrt{2} \times \frac{1}{2} = 0[/tex]
2
[tex]sin {60}^{0} - cos {30}^{0} \\ \sqrt{3} \times \frac{1}{2} - \sqrt{3} \times \frac{1}{2} = 0[/tex]
3
[tex] - cos {60}^{0} + sin {30}^{0} \\ - \frac{1}{2} + \frac{1}{2} = 0[/tex]
4
[tex] \sqrt{2} \times \frac{1}{2} \times 1 = \sqrt{2} \times \frac{1}{2}[/tex]
5
1/2 [tex] \sqrt{2}[/tex] x 1 = 1/2 [tex] \sqrt{2}[/tex]