Matematika

Pertanyaan

diketahui deret aritmatika: 60+54+48+42+.. maka jumlah 20 suku pertama

2 Jawaban

  • Un = a + (n-1) b
    U20 = 60 + (20-1) -6
    = 60 + 19 x -6
    = 60 - 114
    = -54

    Sn = n/2 (a+Un)
    S20 = 20/2 (60 + (-54))
    = 10 x 6
    = 60
  • a = 60
    b = 54 - 60 = -6

    Sn = 1/2 x n ( 2a + (n-1) b )
    S20 = 1/2 x 20 ( 2(60) + ( 20-1) -6 )
    S20 = 10 ( 120 + (19)-6 )
    S20 = 10 ( 120 + ( - 114 ) )
    S20 = 10 ( 6 )
    S20 = 60

    sekian

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