diketahui bilangan a, b, c. jika acb + bca + bac + cab + cba = 3167 tentukan bilangan a, b, dan c tersebut

acb+bca+bac+cab+cba = 100x(a+b+b+c+c) + 10x(c+c+a+a+b) + (b+a+c+b+a) = 3167
= 100x(a+b+b+c+c) + 10x(a+a+b+c+c) + (a+a+b+b+c) = 3167
= 100x(a+2b+2c) + 10x(2a+b+2c) + (2a+2b+c) = 3167
a(100+20+2) + b(200+10+2) + c(200+20+1) = 3167
122a + 212b + 221c = 3167
a = 3
b = 8
c = 5