besar sudut CED = pakai cara!!

4x + 4 + 3x + 8 + 5x = 180
12x + 12 = 180
12x = 168
x = 14
sudut CED = 3x + 8
= 3 × 14 + 8
= 42 + 8
= 50 ( a )

∠AEC + ∠CED + ∠DEB = 180° ( karena sudut berpelurus )

4x + 4 + 3x + 8 + 5x = 180°
12x + 12 = 180°
12x = 180° - 12
12x = 168°
[tex]x = \frac{168}{7} [/tex]
x = 14°

∠CED
= 3x + 8
= 3(14°) + 8
= 42° + 8
= 50° [ opsi. A ]