diketahui f(×+1)= ×kuadrat + 1 dan g(×)= 2×+4, nilai dari (g o f)(2)=

y = x+1
Invers y = x-1

f(x+1) = x²+1
fx = (x-1)²+1
= x²-2x+2

gof (x) = g (fx)
= 2(fx)+4
= 2(x²-2x+2)+4
= 2x²-4x+8
gof(2) = 2.2²-4.2+8
= 8

f(x+1) = x^2 + 1
f(x+1) = (x+1)^2 -2(x+1) + 2
f(x) = x^2 - 2x + 2

(gof) (x)
= g(f(x))
= g (x^2 -2x + 2)
= 2(x^2 -2x + 2) + 4
= (2x^2 - 4x + 4) + 4
= 2x^2 - 4x + 8

Semoga membantu :)