bantuin dong please makasih .

BG = r√2
AG = r√3

Dit : Cosα

Jawab :

BG² = AB² + AG² - 2.AB.AG.Cosα
(r√2)² = r² + (r√3)² - 2.r².r√3.Cosα
2r² = r² + 3r² - 2√3.r³.Cosα
2r² = 4r² - 2√3.r³.Cosα
2√3.r³.Cosα = 4r² - 2r²
2√3.r³.Cosα = 2r²
Cosα = 2r² / 2√3.r³
Cosα = 1/√3r

Disederhanakan :
1/√3 × √3/√3 = 1/3 √3 (C)

maaf kalau misal ada salah, semoga benar